A battery of 24 cells,each of emf 1.5,V and i | vedclass

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(A) Let $m$ be the number of rows connected in parallel and $n$ be the number of cells in each row connected in series. The total number of cells is $

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$2$ rows of $12$ cells connected in series

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(A) Let $m$ be the number of rows connected in parallel and $n$ be the number of cells in each row connected in series. The total number of cells is $N = n 	imes m = 24$.For maximum current in an external resistance $R$,the condition is $R = \frac{nr}{m}$,where $r$ is the internal resistance of each cell.Given $R = 12\,\Omega$ and $r = 2\,\Omega$,we have $12 = \frac{n 	imes 2}{m}$,which simplifies to $n = 6m$.Substituting $n = 6m$ into $n 	imes m = 24$,we get $(6m) 	imes m = 24$,so $6m^2 = 24$,which means $m^2 = 4$,so $m = 2$.Then $n = 6 	imes 2 = 12$.Thus,there are $2$ rows,each containing $12$ cells connected in series.

$A$ battery of $24$ cells,each of emf $1.5\,V$ and internal resistance $2\,\Omega$,is to be connected in order to send the maximum current through a $12\,\Omega$ resistor. The correct arrangement of cells will be:

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